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A sample of CO² was confined to a container at constant pressure and number of molecules. when the temperature of applied to the gas was 323.15 K, the volume occupied by the gas became 5.00L.

How much temperature must be exerted to increase the volume of gas 6.00L?

CHARLES' LAW

Given: Sample. Give Solution:
T1: 323.15 K
V1: 5.00 L
V2: 6.00 L
P2:?

please need help to answer this.
and give the Solutions.
thanks ahead...​​


Sagot :

Answer:

v- 5L

T-323.15k

V2-6L

T2=?

5L=6L/323.15k=T2

=323.15×6L

=1938.9÷5

=387.78k

I hope it help u

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